![]() Before we calculate though, it’s always a good idea to check out the units. Times 10 to the negative three meters per second.įinally, we’re ready to substitute all these values into the formula to find □. So, Δ□ sub □ equals 0.24 times 10 to the negative two meters per second or 2.4 Second, which equals 0.24 centimeters per second.īefore we move on though, let’s recall that centi- means 10 to the negative two. So Δ□ sub □ is given by 0.84 centimeters per second minus 0.60 centimeters per We can choose to calculate the change in speed between the second and third layers ofįluid. The last term we need in order to calculate the dynamic viscosity is Δ□ sub □, theĬhange in the speeds of any two adjacent layers. Again recalling that milli- means 10 to the negative three, we have that Δ□ equalsĠ.5 times 10 to the negative three or 5.0 times 10 to the negative four meters. So the height of each layer is given by 2.5 millimeters divided by five or 0.5 From the diagram, we can count one, two, three, four, five different layers. We were told that, in total, the fluid is 2.5 millimeters deep. Next, for Δ□, we need to determine the height of each fluid layer. Each side is 35 centimeters or 0.35 meters long, so the area □ equals 0.1225 meters We’ve also been given the side lengths of the square top plate, so we can calculate So we can write the force as 0.50 times 10 to the negative three newtons, which isĮqual to 5.0 times 10 to the negative four newtons. Let’s recall that the prefix milli- means 10 to the negative three. We already know that the force on the top plate, □, equals 0.50 millinewtons. And Δ□ sub □ is the change in speed between adjacent fluid layers. Over □ times Δ□ over Δ□ sub □, where □ is the force applied on the top To find the dynamic viscosity, □, of this fluid, we’ll use the formula □ equals □ Let’s start out by writing down the value of the force □ and then clearing space on What is the dynamic viscosity of the liquid? The liquid in contact with the top and bottom plates moves at the same speed as the The speeds of the layers of the liquid between the top and bottom plates are shown in Is 2.5 millimeters deep, as shown in the diagram. Millinewtons, moving at a constant speed over the surface of a viscous liquid that A thin plate of mass 2.5 grams is pushed by a constant force □ equals 0.50
0 Comments
Leave a Reply. |